Skip to main content
Arduino

Return to Question

Minor fixes
Source Link
edit approved Jan 4, 2016 at 10:53
Greenonline
edit approved Jan 4, 2016 at 10:53
Greenonline
  • 3.2k
  • 7
  • 37
  • 49

arduino uno Arduino Uno - why doesn't memory leak doesn't crash the program?

I wrote this test program:

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

curiouslyCuriously, the ledLED keeps blinking and so it means the loops continues. My

My question is how can it continue when it runs out of heap memory like that?

arduino uno - why memory leak doesn't crash the program?

I wrote this test program:

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

curiously, the led keeps blinking and so it means the loops continues. My question is how can it continue when it runs out of heap memory like that?

Arduino Uno - why doesn't memory leak crash the program?

I wrote this test program:

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

Curiously, the LED keeps blinking and so it means the loops continues.

My question is how can it continue when it runs out of heap memory like that?

add code highlighting
Source Link
edit approved Jan 2, 2016 at 19:40
user3704293
edit approved Jan 2, 2016 at 19:40
user3704293
  • 471
  • 7
  • 20

I wrote this test program:

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

curiously, the led keeps blinking and so it means the loops continues. My question is how can it continue when it runs out of heap memory like that?

I wrote this test program:

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

curiously, the led keeps blinking and so it means the loops continues. My question is how can it continue when it runs out of heap memory like that?

I wrote this test program:

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

curiously, the led keeps blinking and so it means the loops continues. My question is how can it continue when it runs out of heap memory like that?

added 36 characters in body
Source Link
Majenko
Majenko
  • 105.9k
  • 5
  • 82
  • 139

I wrote this test program: void loop() { digitalWrite(13,1); delay(300); digitalWrite(13,0); delay(300); void *a = malloc(10000000000000000000000000000000000000000); } curiously

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

curiously, the led keeps blinking and so it means the loops continues. My question is how can it continue when it runs out of heap memory like that?

I wrote this test program: void loop() { digitalWrite(13,1); delay(300); digitalWrite(13,0); delay(300); void *a = malloc(10000000000000000000000000000000000000000); } curiously, the led keeps blinking and so it means the loops continues. My question is how can it continue when it runs out of heap memory like that?

I wrote this test program:

void loop()
{
    digitalWrite(13,1);
    delay(300);
    digitalWrite(13,0);
    delay(300);
    void *a = malloc(10000000000000000000000000000000000000000);
}

curiously, the led keeps blinking and so it means the loops continues. My question is how can it continue when it runs out of heap memory like that?

Source Link
ijklr
ijklr
  • 121
  • 2