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Replace the line:

  if (A0 == HIGH) {

by this one:

  if (digitalRead(A0) == HIGH) {

If you plan on using the pin back as an analog input, use something like this:

  if (analogRead(A0) > 512) {

The explanation is what Ignacio said: you were comparing the pin "name" A0 directly to HIGH instead of reading from the input named A0. To make it clearer, the two lines are equivalent:

if (A0 == HIGH)
if (0 == HIGH)

Get it?

There's more about what pin names to use with digitalRead() and analogRead() here:

Replace the line:

  if (A0 == HIGH) {

by this one:

  if (digitalRead(A0) == HIGH) {

If you plan on using the pin back as an analog input, use something like this:

  if (analogRead(A0) > 512) {

The explanation is what Ignacio said: you were comparing the pin "name" A0 directly to HIGH instead of reading from the input named A0. To make it clearer, the two lines are equivalent:

if (A0 == HIGH)
if (0 == HIGH)

Get it?

There's more about what pin names to use with digitalRead() and analogRead() here:

Replace the line:

  if (A0 == HIGH) {

by this one:

  if (digitalRead(A0) == HIGH) {

If you plan on using the pin back as an analog input, use something like this:

  if (analogRead(A0) > 512) {

The explanation is what Ignacio said: you were comparing the pin "name" A0 directly to HIGH instead of reading from the input named A0. To make it clearer, the two lines are equivalent:

if (A0 == HIGH)
if (0 == HIGH)

Get it?

There's more about what pin names to use with digitalRead() and analogRead() here:

added 5 characters in body
Source Link
Ricardo
Ricardo
  • 3.4k
  • 2
  • 26
  • 55

Replace the line:

  if (A0 == HIGH) {

by this one:

  if (digitalRead(A0) == HIGH) {

If you plnaplan on using the pin back as an analog input, use something like this:

  if (analogRead(A0) > 512) {

The explanation is what Ignacio said: you were comparing the pin "name" A0 directly to HIGH instead of reading from the input named A0 represents. To make it clearer, the two lines are equivalent:

if (A0 == HIGH)
if (0 == HIGH)

Get it?

There's more about what pin names to use with digitalRead() and analogRead() here:

Replace the line:

  if (A0 == HIGH) {

by this one:

  if (digitalRead(A0) == HIGH) {

If you plna on using the pin as an analog input, use something like this:

  if (analogRead(A0) > 512) {

The explanation is what Ignacio said: you were comparing the pin "name" A0 directly to HIGH instead of reading from the input A0 represents. To make it clearer, the two lines are equivalent:

if (A0 == HIGH)
if (0 == HIGH)

Get it?

Replace the line:

  if (A0 == HIGH) {

by this one:

  if (digitalRead(A0) == HIGH) {

If you plan on using the pin back as an analog input, use something like this:

  if (analogRead(A0) > 512) {

The explanation is what Ignacio said: you were comparing the pin "name" A0 directly to HIGH instead of reading from the input named A0. To make it clearer, the two lines are equivalent:

if (A0 == HIGH)
if (0 == HIGH)

Get it?

There's more about what pin names to use with digitalRead() and analogRead() here:

Post Migrated Here from electronics.stackexchange.com (revisions)
Source Link
Ricardo
Ricardo
  • 3.4k
  • 2
  • 26
  • 55

Replace the line:

  if (A0 == HIGH) {

by this one:

  if (digitalRead(A0) == HIGH) {

If you plna on using the pin as an analog input, use something like this:

  if (analogRead(A0) > 512) {

The explanation is what Ignacio said: you were comparing the pin "name" A0 directly to HIGH instead of reading from the input A0 represents. To make it clearer, the two lines are equivalent:

if (A0 == HIGH)
if (0 == HIGH)

Get it?