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(a:x)!y|(s,_:_t)<-span(/=a)y=x!([e|e<-a:s++a:y)|1>0=x!(as,t>[]]++a:y) _!y=reverse y
Attempt This Online!Attempt This Online!
I'm a bit rusty with the Haskell golf.
(a:x)!y|(s,_:_)<-span(/=a)y=x!(a:s++a:y)|1>0=x!(a:y) _!y=reverse y
Attempt This Online!
(a:x)!y|(s,t)<-span(/=a)y=x!([e|e<-a:s,t>[]]++a:y) _!y=reverse y
