In this example we shall show you how to parse a URL. Class URL represents a Uniform Resource Locator, a pointer to a “resource” on the World Wide Web. A resource can be something as simple as a file or a directory, or it can be a reference to a more complicated object, such as a query to a database or to a search engine. To parse a URL one should perform the following steps:
- Create a URL object from the String representation.
- Use
getProtocol()API method to get the protocol name of this URL, that is HTTP protocol. - Use
getHost()API method to get the host name of this URL, if applicable. - Use
getPort()API method to get the port number of this URL. - Use
getPath()API method to get the path part of this URL,
as described in the code snippet below.
package com.javacodegeeks.snippets.core;
import java.net.MalformedURLException;
import java.net.URL;
public class ParseURLExample {
public static void main(String[] args) {
// Create a URL
try {
URL url = new URL("http://www.javacodegeeks.com:80/");
String protocol = url.getProtocol();
String host = url.getHost();
int port = url.getPort();
String path = url.getPath();
System.out.println("URL created: " + url);
System.out.println("protocol: " + protocol);
System.out.println("host: " + host);
System.out.println("port: " + port);
System.out.println("path: " + path);
}
catch (MalformedURLException e) {
System.out.println("Malformed URL: " + e.getMessage());
}
}
}
Output:
URL created: http://www.javacodegeeks.com:80/
protocol: http
host: www.javacodegeeks.com
port: 80
path: /
This was an example of how to parse a URL in Java.
