update

Author: coder-xiaomo

README.md

@@ -1,6 +1,6 @@
 # 力扣题库（完整版）
 
-> 最后更新日期： **2022.12.24**
+> 最后更新日期： **2023.01.04**
 >
 > 使用脚本前请务必仔细完整阅读本 `README.md` 文件
 

leetcode-cn/origin-data.json

@@ -0,0 +1,93 @@
+{
+    "data": {
+        "question": {
+            "questionId": "2658",
+            "questionFrontendId": "2519",
+            "categoryTitle": "Algorithms",
+            "boundTopicId": 2034838,
+            "title": "Count the Number of K-Big Indices",
+            "titleSlug": "count-the-number-of-k-big-indices",
+            "content": null,
+            "translatedTitle": null,
+            "translatedContent": null,
+            "isPaidOnly": true,
+            "difficulty": "Hard",
+            "likes": 0,
+            "dislikes": 0,
+            "isLiked": null,
+            "similarQuestions": "[]",
+            "contributors": [],
+            "langToValidPlayground": null,
+            "topicTags": [
+                {
+                    "name": "Binary Indexed Tree",
+                    "slug": "binary-indexed-tree",
+                    "translatedName": "树状数组",
+                    "__typename": "TopicTagNode"
+                },
+                {
+                    "name": "Segment Tree",
+                    "slug": "segment-tree",
+                    "translatedName": "线段树",
+                    "__typename": "TopicTagNode"
+                },
+                {
+                    "name": "Array",
+                    "slug": "array",
+                    "translatedName": "数组",
+                    "__typename": "TopicTagNode"
+                },
+                {
+                    "name": "Binary Search",
+                    "slug": "binary-search",
+                    "translatedName": "二分查找",
+                    "__typename": "TopicTagNode"
+                },
+                {
+                    "name": "Divide and Conquer",
+                    "slug": "divide-and-conquer",
+                    "translatedName": "分治",
+                    "__typename": "TopicTagNode"
+                },
+                {
+                    "name": "Ordered Set",
+                    "slug": "ordered-set",
+                    "translatedName": "有序集合",
+                    "__typename": "TopicTagNode"
+                },
+                {
+                    "name": "Merge Sort",
+                    "slug": "merge-sort",
+                    "translatedName": "归并排序",
+                    "__typename": "TopicTagNode"
+                }
+            ],
+            "companyTagStats": null,
+            "codeSnippets": null,
+            "stats": "{\"totalAccepted\": \"51\", \"totalSubmission\": \"64\", \"totalAcceptedRaw\": 51, \"totalSubmissionRaw\": 64, \"acRate\": \"79.7%\"}",
+            "hints": [
+                "The intended solution uses Fenwick Tree.",
+                "Let’s describe the solution for counting the number of elements smaller than nums[i] in the range [0, i - 1], and counting in the range [i + 1, nums.length - 1] can be done similarly by simply reversing the array.",
+                "Iterate from left to right and maintain the Fenwick Tree. Save the value of the query(nums[i]) and update nums[i] + 1 by 1."
+            ],
+            "solution": null,
+            "status": null,
+            "sampleTestCase": "[2,3,6,5,2,3]\n2",
+            "metaData": "{\n  \"name\": \"kBigIndices\",\n  \"params\": [\n    {\n      \"name\": \"nums\",\n      \"type\": \"integer[]\"\n    },\n    {\n      \"type\": \"integer\",\n      \"name\": \"k\"\n    }\n  ],\n  \"return\": {\n    \"type\": \"integer\"\n  }\n}",
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+            "judgeType": "large",
+            "mysqlSchemas": [],
+            "enableRunCode": true,
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+}