unexpected T_IF, if statement in array

Question

I can't figure out why I get Parse error: syntax error, unexpected T_IF on line 6.

 $sf = array ( 

            "name" => $firstname . ' ' . $lastname,
            "email" => $email,
            "address" => $shipping_address_1 . if(!empty($shipping_address_2 )) { echo ", " . $shipping_address_2 }
            );
            print_r($sf);

I want to check if $shipping_address_2 is not empty, and if it's not, then display it.

Because the if statement is invalid there. Statements cannot be used inside expressions (apart from expression statements). — Felix Kling
– Felix Kling, Commented May 10, 2012 at 20:40

user267885 · Accepted Answer · 2012-05-10 20:41:30Z

2

Because your code is wrong. You cannot put an if statement inside the array initialization.

answered May 10, 2012 at 20:41

user267885

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Comments

Jeff Lambert · Accepted Answer · 2012-05-10 20:41:46Z

2

Not 100% sure, but you should be able to use a ternary operator...

"address" => $shipping_address_1 . 
    (!empty($shipping_address_2 )) ? 
        ", " . $shipping_address_2 : // This gets executed if condition is true
        ""    // This gets executed if the condition is false

answered May 10, 2012 at 20:41

Jeff Lambert

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4 Comments

Felix Kling Over a year ago

Nitpick: It's a ternary operator and the conditional operator ;)

Jeff Lambert Over a year ago

@Felix wow, never even heard the distinction before. Updated and thanks :)

Felix Kling Over a year ago

I didn't know that either for a long time ;)

user267885 Over a year ago

But since there is often only one ternary operator in programming languages, it can also be THE ternary operator.

Baba · Accepted Answer · 2012-05-10 20:42:09Z

1

Replace

 "address" => $shipping_address_1 . if(!empty($shipping_address_2 )) { echo ", " . $shipping_address_2 }

With

"address" => $shipping_address_1 . (empty($shipping_address_2) ? null :  ", " . $shipping_address_2)

answered May 10, 2012 at 20:42

Baba

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