Changing xml content when converting it to HTML via xslt

Question

I need to transform a XML file to HTML format via XSLT and java. One of the tags contains the link of intranet page like:

http://mycompany.com&mypage=xyz&version=999

now I want to use this value in href attribute in generated html.

Before using this value I want to get rid of "amp;" and change the url like appending it with username.

Can I do it via some XSLT function or I have to replace it in java code ?

Dimitre Novatchev · Accepted Answer · 2012-07-26 04:31:39Z

2

Can I do it via some XSLT function or I have to replace it in java code ?

This is trivial in XSLT.

This transformation:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:param name="pUserName" select="'someUser'"/>

 <xsl:template match="someLink">
     <a href="{substring-before(., '?')}/{$pUserName}">someLink</a>
 </xsl:template>
</xsl:stylesheet>

When applied on this XML document:

<someLink>http://mycompany.com?mypage='xyz'&amp;version='999'</someLink>

produces the wanted, correct result:

<a href="http://mycompany.com/someUser">someLink</a>

answered Jul 26, 2012 at 4:31

Dimitre Novatchev

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2 Comments

Kshitij Gupta Over a year ago

Thanks for your answer, I will try it and let you know. Also can I give userName dynamically via some system properties ?

Dimitre Novatchev Over a year ago

@KshitijGupta: Most probably this can be done -- how to pass external parameters to the XSLT transformation is implementation (vendor) dependent. Read the documentation of the XSLT processor that you are using and there must exist a section on this topic. If you can't find this information, ask a new question and someone would probably share how this should be done.

Joe M · Accepted Answer · 2012-07-26 04:35:27Z

1

try fn:replace(string,pattern,replace) and fn:concat(string,string,...)

Returns a string that is created by replacing the given pattern with the replace argument Example: replace("Bella Italia", "l", "") Result: 'Be*a Ita*ia'

Example: replace("Bella Italia", "l", "") Result: 'Bea Itaia'

fn:concat(string,string,...) Returns the concatenation of the strings Example: concat('XPath ','is ','FUN!') Result: 'XPath is FUN!'

Ref: http://www.w3schools.com/xpath/xpath_functions.asp

Note: Make sure you are using XSLT version 2.0, as the replace function is only available in XSLT version 2.0, not in version 1.0

answered Jul 26, 2012 at 4:35

Joe M

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Comments

Community · Accepted Answer · 2017-05-23 10:34:51Z

0

First your given link is not working ,

http://mycompany.com?mypage=xyz&version=999.

I think simply you want to transform your xml into html in java.

for that visit this discussion. suggestions-for-a-java-based-templating-engine

This is done by template engine, widely used template engines in java are Freemarker and velocity. others are also available.

Here is list of Java Template Engines. Java Template Engines

edited May 23, 2017 at 10:34

CommunityBot

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answered Jul 26, 2012 at 4:31

rogue lad

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Comments

maneesh · Accepted Answer · 2012-07-26 04:44:34Z

0

If you want to write the & characters in the URL as it is instead of & use disable output escaping. Use concat function to append anything else you want to the url.

<xsl:value-of select="$url" disable-output-escaping="yes"/>

answered Jul 26, 2012 at 4:44

maneesh

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