passing value from one html to another using jquery load function

Question

I am stuck in a strange problem. The code I am using is working fine in one page but it is not working for another page. I tried everything I could, I even changed the document header to match the page which is working but none is working for me. And then I created a fresh page and typed only the coding that passing the content, but it didn't work in the new page too. I am totally confused and don't know what to do.

Code:

<head>
<script type="text/javascript">
$(document).ready(function(){
$('#bill2').load('http://website.com/fare.html #bill2')
})
</script>
</head>

<body>
<fieldset id="bill2">
</fieldset>
</body>

This code works in one page and not working in another, please tell me am I missing something?

re-check if the jQuery is included! can't see it here inside the head or body tags!! — Vishal
– Vishal, Commented Sep 27, 2012 at 9:57
Check What do you mean by doesn't work ? and also check for js error in web console of browsers. — mtk
– mtk, Commented Sep 27, 2012 at 9:58

swapnesh · Accepted Answer · 2012-09-27 09:58:37Z

1

Try this and let me know --

<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#bill2').load('http://website.com/fare.html#bill2');
});
</script>
</head>

<body>
<fieldset id="bill2">
</fieldset>
</body>

answered Sep 27, 2012 at 9:58

swapnesh

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1 Comment

A Mohammed Hussain Over a year ago

It worked, thanks a lot, It seems I have added jquery somewhere in the working page.

CRDave · Accepted Answer · 2012-09-27 10:03:01Z

0

This is not answer but I think i should not write this in comment.

Try this full syntax to fig out error

$("#success").load("xxx.php", function(response, status, xhr) 
{
  if (status == "error") 
  {
    var msg = "Sorry but there was an error: ";
    $("#error").html(msg + xhr.status + " " + xhr.statusText);
  }
});

answered Sep 27, 2012 at 10:03

CRDave

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