Regex: Match url string in the middle of another string

Question

Learning regexp but currently I'm a bit stucked with such pattern..

I need to match my string inside url string, example:

If url contains string '/example/regex' it should return true.

/REGEXFOR:'/example/regex'/.test('http://test.com/example/regex/new') // => true
/REGEXFOR:'/example/regex'/.test('http://test.com/example/regex/new/boo') // => false

Thanks!

It still isn't clear in the question what you wish to do. Both the examples you listed contains the string, but only one should be valid, why? — melwil
– melwil, Commented May 27, 2013 at 14:42

Scipion · Accepted Answer · 2013-05-27 14:39:59Z

1

in your case using $ you can indicate the end of the regex

/\/example\/regex\/\w*$/.test('http:\/\/test.com\/example\/regex\/new') => true
/\/example\/regex\/\w*$/.test('http:\/\/test.com\/example\/regex\/new\/boo') => false

if you don't want any slash more use \w* for letters and numbers characters

answered May 27, 2013 at 14:39

Scipion

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melwil · Accepted Answer · 2013-05-27 14:36:37Z

0

You just escape the backslash and you need to clean it a bit;

 /\/example\/regex/.test('http://test.com/example/regex/new/boo')

According to what you gave as examples, both should validate, though.

answered May 27, 2013 at 14:36

melwil

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2 Comments

Kosmetika Over a year ago

but this should return false

melwil Over a year ago

Why should this return false? It contains '/example/regex'.

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