Split array into three separate arrays

Question

I have an array and I want to split that array into 3 parts or 3 arrays.

1st array contains -> AppName
2nd array contains -> Description
3rd array contains -> Icon

Here is the json array I want to split,

Deviceinfo =   (
                {
            Appname = App;
            Description = "This is test app";
            Icon = "57.png";
        }
    );
}

Here is my code for this,

NSMutableArray *firstArray = [NSMutableArray array];
NSMutableArray *secondArray = [NSMutableArray array];
NSMutableArray *thirdArray = [NSMutableArray array];

for (int i = 0; i < [json count]; i++) {
    NSArray *tempArray = [[json objectAtIndex:i]componentsSeparatedByString:@""];
    [firstArray addObject:[tempArray objectAtIndex:0]];
    [secondArray addObject:[tempArray objectAtIndex:1]];
    if ([tempArray count] == 3)
    {
        [thirdArray addObject:[tempArray objectAtIndex:2]];
    }
}
NSLog(@"yourArray: %@\nfirst: %@\nsecond: %@\nthird: %@", json, firstArray, secondArray, thirdArray);

I observe a crash in the code at this line,

NSArray *tempArray = [[json objectAtIndex:i]componentsSeparatedByString:@""];

I don't understand what is going wrong here. Any pointers to solve this issue?

You do not have a JSON array. What you posted is a single dictionary with one key/value pair. The value is an array containing one dictionary. The inner dictionary has 3 key/value pairs. — rmaddy
– rmaddy, Commented Sep 3, 2013 at 5:52

Nitin Gohel · Accepted Answer · 2013-09-03 06:19:17Z

1

I think you can using below code i hope this help's you :-

NSMutableArray *firstArray = [NSMutableArray array];
NSMutableArray *secondArray = [NSMutableArray array];
NSMutableArray *thirdArray = [NSMutableArray array];

NSDictionary *jsonArray = [NSJSONSerialization JSONObjectWithData: jsonResponse options: NSJSONReadingMutableContainers error: &e]; 

 //here is first i load with Dicutionary bcz if into your Json you have may be multiple Dictuionary so you then you can load purticular dictionary as bellow line

EDIT

  NSArray * responseArr = jsonArray[@"Deviceinfo"];

  firstArray = [responseArr valueForKey:@"Appname"];
  secondArray = [responseArr valueForKey:@"Description"];
  thirdArray = [responseArr valueForKey:@"Icon"];

if you have multiple Deviceinfo dictionary in to your Json then you could use For loop

 //    NSArray * responseArr = jsonArray[@"Deviceinfo"];
 //      for (NSDictionary *dict in responseArr) {

 //        [firstArray addObject:[dict valueForKey:@"Appname"];
 //        [secondArray addObject:[dict valueForKey:@"Description"];
 //       [thirdArray addObject:[dict valueForKey:@"Icon"];
 //     }

edited Sep 3, 2013 at 6:19

answered Sep 3, 2013 at 5:40

Nitin Gohel

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5 Comments

Nitin Gohel Over a year ago

@H2CO3 thx for edit i already given answer with valueForKey

rmaddy Over a year ago

Couldn't you eliminate the loop and do: NSArray *firstArray = [responseArr valueForKey:@"Appname"];?

Nitin Gohel Over a year ago

@rmaddy yes i edit that for loop not requered bcz there is only one dictionary of Deviceinfo so we can use as par your suggestion for loop only req while in json have multiple json dictionary. thank you for your guidance :)

rmaddy Over a year ago

You don't need the loop even if there are multiple dictionaries in the array. That's the point of valueForKey:. It will grab the value from all of the dictionaries and give you an array back.

Nitin Gohel Over a year ago

well i follow this logic that you already put as an Answer take a look stackoverflow.com/questions/18415329/…

Nazik · Accepted Answer · 2013-09-03 05:53:12Z

0

NSMutableArray *firstArray = [[NSMutableArray alloc]init];
NSMutableArray *secondArray = [[NSMutableArray alloc]init];
NSMutableArray *thirdArray = [[NSMutableArray alloc]init];

NSDictionary *list =[NSJSONSerialization JSONObjectWithData:data
                                                                options:kNilOptions error:&error];

 NSArray * tempArray = jsonArray[@"Deviceinfo"];
for (NSDictionary *list in tempArray)
{
  [firstArray addObject:[list objectForKey:@"Appname"];
   [secondArray addObject:[list objectForKey:@"Description"];
   [thirdArray addObject:[list objectForKey:@"Icon"];
 }

Then try

NSLog(@"yourArray: %@\nfirst: %@\nsecond: %@\nthird: %@", tempArray, firstArray, secondArray, thirdArray);

edited Sep 3, 2013 at 5:53

answered Sep 3, 2013 at 5:41

Nazik

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2 Comments

JustSid Over a year ago

valueForKey: (lowercase, by the way), is KVO. To access an object from a dictionary you should use objectForKey: instead.

Nazik Over a year ago

@JustSid, changed, thnx for info.

abhishekkharwar · Accepted Answer · 2013-09-03 05:54:23Z

0

NSData *jsonData = [NSData dataWithContentsOfURL:[NSURL URLWithString:@"http://url.to.your.json"]];

NSArray *jsonObjects = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableContainers error:nil];

NSMutableArray *appNameArray = [NSMutableArray array];
NSMutableArray *discriptionArray = [NSMutableArray array];
NSMutableArray *iconArray = [NSMutableArray array];

for(NSDictionary *dictionary in jsonObjects)
{
     [appNameArray adddObject:[dictionary valueForKey:@"Appname"];
     [appNameArray adddObject:[dictionary valueForKey:@"Description"];
     [appNameArray adddObject:[dictionary valueForKey:@"Icon"];
}

edited Sep 3, 2013 at 5:54

answered Sep 3, 2013 at 5:43

abhishekkharwar

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5 Comments

abhishekkharwar Over a year ago

can you please try valueForKey instead of objectForKey

user529758 Over a year ago

@JitendraDeore Oh yes, it does work. Apple's code is of excellent high quality. It's just that you perhaps don't know how to use it properly. It would be beneficial if you could elaborate as to how it is "not working", because we are not mind readers, and then we could actually help you solve your problem.

JustSid Over a year ago

Will re-upvote when you fix valueForKey:. Like @H2CO3 pointed out, objectForKey: works, valueForKey: on the other hand is for KVO and using it to access objects in a dictionary is wrong.

user529758 Over a year ago

@JitendraDeore So does objectForKey:.

user529758 Over a year ago

@JustSid Well, actually, it's not wrong, it's just not preferred, because it's confusing. valueForKey: works just like objectForKey: does, except when the key is a string and it starts with an @ character, because then it does indeed return KVO values.

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