A good way to write a 1 byte char array into a binary file created by C++

Question

I need to parse a binary file created by C++ and overwrite a 4 char long char array in that file, for example change the original char array of ABCD to WXYZ.

I know exactly the position in terms of bytes of the that char array. I tried RandomAccessFile which let me go to the position easily. But I cannot make the rest work for me right now.

Is the RandomAccessFile a right way to go?

I know I have to do some conversion from 2 bytes char to one byte char.

Anybody has a good way to do this?

Joop Eggen · Accepted Answer · 2013-11-27 16:12:23Z

1

Fine: always try the JavaDoc RandomAccessFile.

long position = ...;
byte[] bytes = new byte[] { (byte)'W', ... };
raf.seek(position);
raf.write(bytes);

answered Nov 27, 2013 at 16:12

Joop Eggen

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NPE · Accepted Answer · 2013-11-27 16:12:02Z

1

RandomAccessFile is fine. As you have already figured out, in C++ char is a single byte, whereas Java uses UTF-16.

The easiest option might be to use byte[4] in your code to represent the 4-character ASCII string.

answered Nov 27, 2013 at 16:12

NPE

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