PHP regex to remove last matching pattern string

Question

I have following URLs

http://domain.com/baby/smile/love/index.txt
http://domain.com/baby/smile/love/toy.txt
http://domain.com/baby/smile/love/car.html
and so on...

using preg regex, how to remove the file name on the right? I guess it's required to match the first dash starting from the right, how I can do this?

So for example if I run something like

$newUrl = preg_match('xxxxxx', '', $url);

or using

$newURL = preg_replace(...);

The $newUrl variable will only contain

http://domain.com/baby/smile/love/

preserving the trailing slash at the end. I was able to do it by using explode(), array_pop(), then implode() to put it back together, just wondering if it 's possible using only regex.

Thank you.

If you need regex free solution , try this echo substr($link1,0,strrpos($link1,'/')+1); — Shankar Narayana Damodaran
– Shankar Narayana Damodaran, Commented Dec 4, 2013 at 6:10

hwnd · Accepted Answer · 2013-12-04 11:04:16Z

4

You can use the following.

function clean($url) {
   $link = substr(strrchr($url, '/'), 1);
   return substr($url, 0, - strlen($link));
}

echo clean($url);

See Live demo

Using regular expression:

$newUrl = preg_replace('~[^/]*$~', '', $url);

See Live demo

edited Dec 4, 2013 at 11:04

answered Dec 4, 2013 at 6:09

hwnd

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1 Comment

user702300 Over a year ago

Thank you so much, this preg_replace is exactly what I was looking for.

user4035 · Accepted Answer · 2013-12-04 06:07:57Z

3

<?php
$str = 'http://domain.com/baby/smile/love/index.txt';

$str = preg_replace('/(.*\/).*/', '$1', $str);
print $str;

Output:

http://domain.com/baby/smile/love/

answered Dec 4, 2013 at 6:07

user4035

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Comments

anubhava · Accepted Answer · 2013-12-04 06:08:39Z

1

This should work:

$s = 'http://domain.com/baby/smile/love/index.txt';

if (preg_match_all('~^.+?/(?!.*?/)~', $s, $matches))
        print_r ( $matches[0] );

OUTPU:

Array
(
    [0] => http://domain.com/baby/smile/love/
)

answered Dec 4, 2013 at 6:08

anubhava

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