Applying regex on each item of a list in Python

Question

If I apply this regex:

re.split(r"(^[^aeiou]+)(?=[aeiouy])", "janu")

on the string "janu", it gives the following result: ['', 'j', 'anu']

Now I want to apply this regex on the following list to get the similar results for each item as above. Can a for loop be used, and if yes, how?

lista = ['janu', 'manu', 'tanu', 'banu']

score 1 · Accepted Answer · 2013-12-05 20:03:18Z

1

You can use a list comprehension:

>>> from re import split
>>> lista = ['janu', 'manu', 'tanu', 'banu']
>>> [split("(^[^aeiou]+)(?=[aeiouy])", x)[1]+"doc" for x in lista]
['jdoc', 'mdoc', 'tdoc', 'bdoc']
>>>

Edit regarding comment:

This will work:

>>> from re import split
>>> lista = ['janu', 'manu', 'tanu', 'banu']
>>> listb = []
>>> for item in lista:
...     data = split("(^[^aeiou]+)(?=[aeiouy])", item)
...     listb.append(data[2]+data[1]+"doc")
...
>>> listb
['anujdoc', 'anumdoc', 'anutdoc', 'anubdoc']
>>>

edited Dec 5, 2013 at 20:03

answered Dec 5, 2013 at 3:59

user2555451

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8 Comments

randomusername Over a year ago

Oh my god, there was only a 10 second delay between our two answers.

user2555451 Over a year ago

@randomusername - Yea, that seems to happen alot on SO. 10 secs isn't the best though. I've sometimes posted simultaneously with someone else.

Coddy Over a year ago

Is there any other way? because it gives nested lists. I have to do an other operation on the list obtained from first item. after completing it, the regexp should move to the second item, and carry on...

Coddy Over a year ago

lista = ['janu', 'manu', 'tanu', 'banu'] after applying this re.split(r"(^[^aeiou]+)(?=[aeiouy])", lista), the regex shouldn't move to the next item until I concatenate the string at index[2] and the suffix doc. for example: first step: ['', 'j', 'anu'] index[1]+doc = jdoc second step: ['', 'm', 'anu'] index[1]+doc = mdoc Third Step: ['', 't', 'anu'] index[1]+doc = tdoc Fourth step: ['', 'b', 'anu'] index[1]+doc = bdoc ultimately the result should look "jdok mdoc tdok bdoc"

user2555451 Over a year ago

@Coddy - Your end result doesn't match your explanation. Do you want "doc" placed at the end or a back-and-forth of "dok" and "doc"?

|

randomusername · Accepted Answer · 2013-12-05 03:59:22Z

0

Use the list comprehension

[re.split(r"(^[^aeiou]+)(?=[aeiouy])", i) for i in list]

You can use a for loop but this is considered the pythonic way to do things.

answered Dec 5, 2013 at 3:59

randomusername

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1 Comment

Coddy Over a year ago

Is there any other way? because it gives nested lists. I have to do an other operation on the list obtained from first item. after completing it, the regexp should move to the second item, and should carry on until the last item in the original list(lista)...

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