Passing array from main and modify it through another function

Question

So my question is that if I have the following code

main(){
char arr[1][3];
foo(arr);
}

void foo(char arr1[1][3]){

arr1[0] = "AB\0";
}

Does this mean that the value in arr from main would also be modified into "AB\0"?

Got it, thank you. Yea, I need to modify my keywords during searching... appreciate your time. — Rozen
– Rozen, Commented Dec 7, 2013 at 5:17

Community · Accepted Answer · 2017-05-23 11:57:32Z

3

Try checking this stack overflow question and answer, it is an age-old question

Passing an array by reference in C?

edited May 23, 2017 at 11:57

CommunityBot

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answered Dec 7, 2013 at 5:13

Tom Pace

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Comments

thomashw · Accepted Answer · 2013-12-07 05:20:38Z

0

Why not test it out yourself?

#include <stdio.h>

void foo(char arr[]);

int main(int argc, char **argv)
{
    char arr[5] = "test";
    printf("%s\n", arr);

    foo(arr);
    printf("%s\n", arr);

    return 0;
}

void foo(char arr[])
{
    arr[0] = 'p';
}

answered Dec 7, 2013 at 5:20

thomashw

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