Django template using variable in two blocks

Question

This is my template code:

{% block content %}
    {% get_latest as latest_posts %}
    <ul>
    {% for post in latest_posts %}
        <li>
            <p><a href="{{ post.get_absolute_url }}">{{ post.title|safe }}</a></p>
        </li>
    {% endfor %}
    </ul>
{% endblock %}

{% block sidebar %}    
    <ul>
    {% for post in latest_posts %}
        <li>
            <p><a href="{{ post.get_absolute_url }}">{{ post.title|safe }}</a></p>
        </li>
    {% endfor %}
    </ul>
{% endblock %}

In the content block the for loop does works, but in the sidebar block I can't use the variable latest_posts. Can anyone help me with this?

Thomas Schwärzl · Accepted Answer · 2014-03-10 16:03:28Z

4

The variable's scope is limited to the containing {% block content %}. You can either repeat the declaration inside {% block sidebar %}, or move it up a level so it's outside of {% block content %}.

example

{% get_latest as latest_posts %}

{% block content %}
    <ul>
    {% for post in latest_posts %}
        <li>
            <p><a href="{{ post.get_absolute_url }}">{{ post.title|safe }}</a></p>
        </li>
    {% endfor %}
    </ul>
{% endblock %}

{% block sidebar %}    
    <ul>
    {% for post in latest_posts %}
        <li>
            <p><a href="{{ post.get_absolute_url }}">{{ post.title|safe }}</a></p>
        </li>
    {% endfor %}
    </ul>
{% endblock %}

or

{% block content %}
    {% get_latest as latest_posts %}
    <ul>
    {% for post in latest_posts %}
        <li>
            <p><a href="{{ post.get_absolute_url }}">{{ post.title|safe }}</a></p>
        </li>
    {% endfor %}
    </ul>
{% endblock %}

{% block sidebar %}  
    {% get_latest as latest_posts %}  
    <ul>
    {% for post in latest_posts %}
        <li>
            <p><a href="{{ post.get_absolute_url }}">{{ post.title|safe }}</a></p>
        </li>
    {% endfor %}
    </ul>
{% endblock %}

edited Mar 10, 2014 at 16:03

Thomas Schwärzl

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answered Mar 10, 2014 at 15:56

John Kugelman

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1 Comment

Mirza Delic Over a year ago

I tried with your first sollution, but doesn't work in both blocks :( and in your second example, i don't wanna do 2 sql queries, any other solution?

Dr.Elch · Accepted Answer · 2014-03-11 11:35:12Z

2

You can use the with statement:

Definition:

with Caches a complex variable under a simpler name. This is useful when accessing an “expensive” method (e.g., one that hits the database) multiple times.

Wrap your existing block into this with clause and you can safe yourself some queries. also it should solve your problem :-) Just remove the {% get_latest as latest_posts %} line

{% with latest_posts=get_latest %}

{% block content %}
    <ul>
    {% for post in latest_posts %}
        <li>
            <p><a href="{{ post.get_absolute_url }}">{{ post.title|safe }}</a></p>
        </li>
    {% endfor %}
    </ul>
{% endblock %}

{% block sidebar %}    
    <ul>
    {% for post in latest_posts %}
        <li>
            <p><a href="{{ post.get_absolute_url }}">{{ post.title|safe }}</a></p>
        </li>
    {% endfor %}
    </ul>
{% endblock %}
{% endwith %}

answered Mar 11, 2014 at 11:35

Dr.Elch

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1 Comment

Mirza Delic Over a year ago

This is good, now i have another problem, my template tag is now {% get_latest_posts 6 'category' as latest_posts %}, how can i use this with with statement?

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