Multidimensional char array in C in function

Question

How to use function in C with array of strings? My code:

void test(char **a){
    printf("%s", a[0]);
}
int main(){
    char b[10][10];
    strcpy(b[0],"abc");
    strcpy(b[1],"dfgd");
    test(b);
    return 0;
}

How to make this example of code work?

The compiler doesn't know the "real" dimensions of the pointed array in function test. I'm quite surprised that it didn't issue a warning on the line test(b). Change char **a to char a[][10]. — barak manos
– barak manos, Commented Dec 27, 2014 at 16:47

Ali Akber · Accepted Answer · 2014-12-28 03:23:51Z

4

You can use :

void test(char a[10][10]){
    printf("%s", a[0]);
}

or

void test(char a[][10]){
    printf("%s", a[0]);
}

or

void test(char (*a)[10]){
    printf("%s", a[0]);
}

int main(){
    char b[10][10];
    strcpy(b[0],"abc");
    strcpy(b[1],"dfgd");
    test(b);
    return 0;
}

All three declarations are perfectly equivalent. Although last one is better.

This answer explains it better

edited Dec 28, 2014 at 3:23

answered Dec 27, 2014 at 17:46

Ali Akber

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3 Comments

Ali Akber Over a year ago

I thought it was very bad :( Because as soon as i asked the question the negative votes were flying like wind :(

πάντα ῥεῖ Over a year ago

You may reopen it (sorry one of the downvotes were mine, and I'm willing to retract them of course if you reopen/undelete the question).

cmaster - reinstate monica Over a year ago

The link is good, but I think you should at least say that all three declarations are perfectly equivalent. I would also add a hint to prefer the last one for clarity.

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