PHP Ajax response parsererror

Question

I am trying to make an ajax call and return a response. The problem is I can't seem to figure out how to get at the response. Here is my javascript code:

$.ajax({
    type: "POST", 
    url: "inc.test.php", 
    data: {list:postData},
    dataType: "json",
    success: function(response){
        if(response.success == 1){
            alert (response.testdata);
            }},
    error: function(jqXHR, textStatus, errorThrown){
        console.log(errorThrown); 
        console.log(textStatus);
        }
    });

Here is my inc.test.php code sending the json data back:

if($result)
    {
    $arr=array(
        "success" => 1,
        "testdata" => 'Testing');
    echo json_encode($arr);
    }

In my Console/Response I see this:

{"success":1,"testdata":"Testing"}

I've read tons of articles and can't seem to figure out whats going on. Please help!

Are you getting an error or are you just looking to deal with the response? — mlewis54
– mlewis54, Commented Oct 25, 2015 at 0:59
inspect the actual request response body in dev tools network and see if there are other characters being returned other than the json — charlietfl
– charlietfl, Commented Oct 25, 2015 at 1:07

dchayka · Accepted Answer · 2023-04-04 14:14:14Z

1

success: function(response) {
  var resp = JSON.parse(response);
  // rest of code ...
  }

May be because you have to parse your code? You didn't specify what the issue is.

edited Apr 4, 2023 at 14:14

answered Oct 25, 2015 at 4:24

dchayka

1,31213 silver badges21 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

A l w a y s S u n n y · Accepted Answer · 2015-10-25 02:36:21Z

0

Did you try using PHP's trim() function before sending the data? i think you have an extra space when you json_encode or use trim().

if($result)
    {
    $arr=array(
        "success" => 1, 
                    ^
        "testdata" => 'Testing');
                     ^
    echo json_encode($arr);
    }

answered Oct 25, 2015 at 2:36

A l w a y s S u n n y

38.8k9 gold badges68 silver badges120 bronze badges

1 Comment

dchayka Over a year ago

That doesn't matter, it's an array declaration so you can have tabs and spaces there to format the code for readability.

Kos M · Accepted Answer · 2021-11-12 08:22:09Z

0

if this is in wordpress , you may forgot to

wp_die();

in the end of php function called by ajax request

answered Nov 12, 2021 at 8:22

Kos M

12 bronze badges

Collectives™ on Stack Overflow

PHP Ajax response parsererror

3 Answers 3

Comments

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related