Python: AttributeError in plotting a 3d surface

Question

I am trying to plot a 3d surface by having coordinates of x,y and values as w1. I have checked the dimensions by shape(), they match. but I receive the error that "AttributeError: 'module' object has no attribute 'plot_surface'"

Code:

import numpy as np
import math
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D

. . .

x = np.arange(xmin, xmax+dx, dx)
z = np.arange(zmin, zmax+dz, dz)
X, Z = np.meshgrid(x, z)
#print X.shape, Z.shape, w1.shape
plt.plot_surface(X, Z, w1)
plt.show()

w1 is defined before, and is a array of values with same dimension as X, Z...I checked by shape() — Soyol
– Soyol, Commented Mar 19, 2016 at 2:11

Soyol · Accepted Answer · 2016-03-19 02:40:55Z

6

This way it worked for me:

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

x = np.arange(xmin, xmax+dx, dx)
z = np.arange(zmin, zmax+dz, dz)
X, Z = np.meshgrid(x, z)
ax.plot_surface(X, Z, w1)
plt.show()

answered Mar 19, 2016 at 2:40

Soyol

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Comments

Christian Jay Santiago · Accepted Answer · 2023-07-20 10:36:19Z

0

import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D

# Define the region bounded by y = sqrt(x) and y = 0
x = np.linspace(0, 3, 100)
y = np.sqrt(x)

# Create a 3D figure
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

# Revolve about the x-axis
ax.plot(x, y, zs=0, label='y = sqrt(x)')
ax.fill_between(x, y, 0, alpha=0.2)
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.set_zlabel('z')
ax.set_title('Solid Revolved about the x-axis')
ax.legend()

plt.show()

answered Jul 20, 2023 at 10:36

Christian Jay Santiago

1

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