Javascript reference error using default operator

Question

I am trying to use the || operator as the "default" operator as described by Crockford at (http://www.crockford.com/javascript/survey.html):

The || operator is commonly called logical or. It can also be called default. If the first operand is false, null, undefined, "" (the empty string), or the number 0, then it returns the second operand. Otherwise, it returns the first operand. This provides a convenient way to specify default values:

value = v || 10; /* Use the value of v, but if v
doesn't have a value, use 10 instead. */

When I type that into the firebug javascript console it reports an error: ReferenceError: v is not defined, and does not go on to set value to 10.

Is that expected behavior?

John Fisher · Accepted Answer · 2010-10-08 21:19:28Z

3

Yes. If you haven't told javascript that "v" is a variable, it will complain. You can do one of two things to correct this:

var v;
value = v || 10;

or

value = window.v || 10;

answered Oct 8, 2010 at 21:19

John Fisher

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1 Comment

JJ Blumenfeld Over a year ago

Thanks. second option looks like what I'm trying to do.

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