How to click on confirmation button using Selenium with Python?

Question

I have the following Code that goes to a URL(www.example.com), and clicks on a link(Example 1). (This part works fine)

from selenium import webdriver

driver = webdriver.Firefox()
driver.get("https://www.example.com")

link = driver.find_element_by_link_text('Example 1')
link.click()

Now, when we click on 'Example 1' link, it opens a confirmation window, with 2 buttons: 'Yes I am authorized user to this site' and 'No I am a new visitor to this site'

So, I wish to click on 'Yes I am authorized user to this site' and then finally enter my log-in credentials. I have written these 2 lines, just below the above code, for clicking on that button. But these don't work.

button = driver.find_element_by_name("'Yes I am authorized user to this site'")
button.click()

Does the button have the quotation marks on it? Because based on your code you're saying the button says 'Yes I am authorized user to this site' — Harrison
– Harrison, Commented Aug 24, 2016 at 14:10
Is there any way you can provide the link to the website, or at the very least screenshots because I don't really see anything wrong with your code. It might have something to do with the site itself. — Harrison
– Harrison, Commented Aug 24, 2016 at 14:13
I have also tried : (1) driver.find_element_by_link_text (2) driver.find_element_by_class_name . But none of these works — Aditya
– Aditya, Commented Aug 24, 2016 at 14:15

Jeril · Accepted Answer · 2016-08-24 14:44:58Z

5

If it is an alert window, you need to use the Alert command.

#import Alert
from selenium.webdriver.common.alert import Alert
from selenium import webdriver

driver = webdriver.Firefox()
driver.get("https://www.example.com")

link = driver.find_element_by_link_text('Example 1')
link.click()
Alert(driver).accept()
#to dismiss alert
#Alert(driver).dismiss()

I think this would have solved your query.

edited Aug 24, 2016 at 14:44

answered Aug 24, 2016 at 14:34

Jeril

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2 Comments

Jeril Over a year ago

can you please share the link where you are trying this?

Wildhammer Over a year ago

Works perfectly in my case!

dblclik · Accepted Answer · 2016-08-25 13:27:37Z

Based on the comment conversation, I would recommend both using an XPATH search (instead of Name or Id) and waiting for elements to be clickable or loaded. When web-driving or web-scraping, pages may intentionally or accidentally load slowly and this can cause issues if you have pauses or waits either hard coded or non-existent. This snippet of code should allow you to search Google using Selenium and Chromedriver (you can modify the driver function to use Firefox or something else if you'd like):

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import ElementNotVisibleException
from selenium.webdriver.chrome.options import Options
from time import sleep

def init_driver(drvr_path):
    chrome_options = Options()
    chrome_options.add_argument("--disable-extensions")
    driver = webdriver.Chrome(drvr_path+'chromedriver.exe',chrome_options=chrome_options)
    driver.wait = WebDriverWait(driver, 5)
    return driver

def lookup(query, driver=None, drvr_path=''):
    driver = None
    if driver is None:
        driver = init_driver(drvr_path)
    driver.implicitly_wait(45) # Allow up to 45 Seconds for page to load
    driver.get("http://www.google.com")
    try:
        box = driver.wait.until(EC.presence_of_element_located((By.XPATH, """//*[@id="lst-ib"]""")))
        box.send_keys(query)
        sleep(3) # Let you see the window open
        button = driver.wait.until(EC.element_to_be_clickable((By.XPATH,"""//*[@id="sblsbb"]/button""")))
        try:
            button.click()
        except ElementNotVisibleException, s:
            print "Error Handled: "+str(s)
            button = driver.wait.until(EC.element_to_be_clickable((By.XPATH,"""//*[@id="sblsbb"]/button""")))
            try:
                button.click()
            except:
                print "Could not search Google..."
                return
        resp=driver.page_source.encode('utf-8')
        with open(query+'.html','wb') as f:
            f.write(resp)
            print 'Wrote the File...'
    except:
        print("Box or Button not found in google.com")
    driver.quit()

For example, if your Chromedriver.exe file was located in your default Python path, you could do something like: lookup('Selenium Python XPATH Examples') and it should download an HTML file of the Google Search results. If you already have a Driver initialized, you could of course pass that to it.

Hope this helps

thebadguy · Accepted Answer · 2016-08-24 17:31:20Z

0

Try this code, hope it will help you

from selenium import webdriver
import time

driver = webdriver.Chrome('path to chromedriver\chromedriver.exe')
driver.get('https://www.example.com')
driver.maximize_window()

link = driver.find_element_by_link_text('Example 1')
link.click()
handles =driver.window_handles # this will give window handles

driver.switch_to.window(handles[1])
button = driver.find_element_by_name("'Yes I am authorized user to this site'")
button.click()

edited Aug 24, 2016 at 17:31

answered Aug 24, 2016 at 17:24

thebadguy

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