C++ Pointer array function pass by address

Question

Need a help, how can i print arr pointer with value of arrfibo[] on fibo function ?

#include <iostream>
using namespace std;

int fibo(int input){

    for(int i=0;i<input;i++){
        if(i<2){
            arrfibo[i] = i;
        }else{
            arrfibo[i] = arrfibo[i-2] + arrfibo[i-1];
        }
    }   
}

main(){
    int inp;
    cout << "Enter number of fibonancci = ";
    cin >> inp;
    int *arr;

    // how can i print arr pointer with value of arrfibo[] on fibo function ?   
}

thanks for any answer,

main() is a syntax error.

melpomene
– melpomene

2016-12-05 00:29:44 +00:00
Commented Dec 5, 2016 at 0:29 — melpomene
– melpomene, Commented Dec 5, 2016 at 0:29

Ufuk Can Bicici · Accepted Answer · 2016-12-05 00:38:23Z

1

int main(){
     int inp;
     cout << "Enter number of fibonacci = ";
     cin >> inp;
     int *arr = new int[inp];
     fibo(inp, arr);
     //Any additional code
     //Delete dynamic memory.
     delete [] arr;
     }

Then modify fibo as:

void fibo(int input, int* arrfibo){

for(int i=0;i<input;i++){
    if(i<2){
        arrfibo[i] = i;
    }else{
        arrfibo[i] = arrfibo[i-2] + arrfibo[i-1];
    }
}   
 //Use arrfibo at your will after this point.
}

edited Dec 5, 2016 at 0:38

answered Dec 5, 2016 at 0:35

Ufuk Can Bicici

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