input hexadecimal number using Unsigned Char Array

Question

I am having problem inputting hexadecimal number using unsigned char array. Code:

unsigned char key[16];
for(int i = 0; i < 16; i++){
    cin>>key[i];
}

It takes single character as one character e.g. - 0x1b is read as 0 x 1 b separately. Please help me.

are you aware how many char are in 0x1b when you use the cin to give that input? — ΦXocę 웃 Пepeúpa ツ
– ΦXocę 웃 Пepeúpa ツ, Commented Jun 19, 2017 at 7:56
Please take the time to read How to Ask a question. In particular, please specify how it isn't working, what is intended and what is the result — Passer By
– Passer By, Commented Jun 19, 2017 at 8:18
There are 4 char in 0x1b and this code also takes it separately. — Nishant Kumar
– Nishant Kumar, Commented Jun 19, 2017 at 19:31

0xBADF00 · Accepted Answer · 2017-06-20 08:27:23Z

1

You can use std::hex.

unsigned int hex = 0;
for (int i = 0; i < 16; i++) {
    std::cin >> std::hex >> hex;
    key[i] = hex;
}

answered Jun 19, 2017 at 9:07

0xBADF00

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