Why is .insert not adding entry text into array (Python)

Question

This part of my code is the problem: I want to add names to Name_List by entering text into the entry widget. Then use the "add" button to insert the item into Name_List by the function add_name.

import tkinter as tk
from tkinter import *

Name_List = []

...

class NamePage(tk.Frame):
    def __init__(self, parent, controller):
        tk.Frame.__init__(self,parent)
        name=StringVar()
        name_entry= tk.Entry(self, text="Enter name:", textvariable=name)
        name_entry.pack()
        add_button= tk.Button(self, text="Add",
                              command=lambda: self.add_name(name))
        add_button.pack()
        To_Role_List= tk.Button(self, text="Assign Roles",
                                command=lambda: self.print_namelist())
        To_Role_List.pack()

    def add_name(self,name,i=0):
        Name_List.insert(i, name)
        print(Name_List)
        i+=1

    def print_namelist(self):
        for i in [0,len(Name_List)]:
            print (Name_List[i])


app=TOS_outline()
app.mainloop()

My result, after entering the name "Alpha" into the Entry widget, appears to be this (using print of course):

[<tkinter.StringVar object at 0x03E7D650>]

What do I need to change/fix?

The indentation is broken in the code in your question

Bryan Oakley
– Bryan Oakley

2017-07-03 20:46:27 +00:00
Commented Jul 3, 2017 at 20:46 — Bryan Oakley
– Bryan Oakley, Commented Jul 3, 2017 at 20:46
Hi Bryan, I just fixed it.

T. Corrie
– T. Corrie

2017-07-03 20:50:26 +00:00
Commented Jul 3, 2017 at 20:50 — T. Corrie
– T. Corrie, Commented Jul 3, 2017 at 20:50

Fran Lendínez · Accepted Answer · 2017-07-03 21:10:26Z

1

If you want to use a python list, dont use a counter or range like:

def add_name(self,name,i=0):
    Name_List.insert(i, name)
    print(Name_List)
    i+=1

def print_namelist(self):
    for i in [0,len(Name_List)]:
        print (Name_List[i])

instead use:

def add_name(self,name):
    Name_List.append(name)
    print(Name_List)

def print_namelist(self):
    for name in Name_List:
        print (name)

And use get() to obtain the value of the StringVar object

nombre = StringVar() 
id_art = IntVar()  
nombre.set("Python para impacientes") 
id_art.set(1)  
blog = ttk.Entry(ventana, textvariable=nombre, width=25) 
arti = ttk.Label(ventana, textvariable=id_art) 
print('Blog:', nombre.get()) 
print('Id artículo:', id_art.get())

Example from: http://python-para-impacientes.blogspot.com.es/2016/02/variables-de-control-en-tkinter.html (Spanish)

edited Jul 3, 2017 at 21:10

answered Jul 3, 2017 at 21:01

Fran Lendínez

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4 Comments

T. Corrie Over a year ago

Unfortunately, I get the same response: ['']

Fran Lendínez Over a year ago

name was declared on __ init __ func and doesnt exists anymore out. Try add_button= tk.Button(self, text="Add", command=lambda: self.add_name(name.get()))

T. Corrie Over a year ago

I still get a [''] when I print the list

T. Corrie Over a year ago

Edit: I figured out the problem. You were right, but it was something else in my code (that was in the ...) causing the problem. I had app.Tk() and app.TOS_outline. After I deleted app.Tk() and moved app.TOS_outline to a different spot, I got the program to work

DYZ · Accepted Answer · 2017-07-03 20:54:49Z

1

You are passing the variable to .insert instead of its value. Name_List.insert(i, name) must be Name_List.insert(i, name.get()).

answered Jul 3, 2017 at 20:54

DYZ

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1 Comment

T. Corrie Over a year ago

I changed it. Now all I get is: ['']

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