Filtering python lists using another list

Question

How to look up if a string in one list is a part of another list:

b_names = ['robert', 'jon', 'arya']
a_names = ['rya', 'fish']


def filterA(name):
for string in b_names:
    if name in string:
        return True
    else :
        return False

final_list = filter(filterA,a_names)

The final_list is empty and should have contained the string rya since rya is present as a substring in the arya from the first list.

What is the error here ?

Wondercricket · Accepted Answer · 2017-07-27 17:52:46Z

1

Your for loop is ending too early.

If name is not in string, it returns False. With Robert being first item in b_names, it ends the loop and does not continue to Jon or Arya. You need to put your return False after your for loop

b_names = ['robert', 'jon', 'arya']
a_names = ['rya', 'fish']


def filterA(name):
    for string in b_names:
        if name in string:
            return True

    return False


final_list = filter(filterA, a_names)
print final_list

>>> ['rya']

answered Jul 27, 2017 at 17:52

Wondercricket

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1 Comment

Varunkumar Manohar Over a year ago

Thanks for spotting I think I somehow have overlooked the filterA logic. Thanks much

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