PHP Regex Match Whitespace

Question

I am having trouble matching the space after content="Wordpress in the following regex

$metatag = '<meta name="generator" content="WordPress 4.8.2">';
$metaregex = '/<meta.*?content="Wordpress.(?<version>.*?)"/';

preg_match($metaregex, $metatag, $matches);

print_r($matches);

Duc Filan · Accepted Answer · 2017-09-24 00:41:52Z

5

It's a typo mistake. Instead of:

$metaregex = '/<meta.*?content="Wordpress.(?<version>.*?)"/';

It should be:

$metaregex = '/<meta.*?content="WordPress.(?<version>.*?)"/';

Notice Wordpress vs WordPress.

Or you can ignore case by using the i modifier:

$metaregex = '/<meta.*?content="wordpress.(?<version>.*?)"/i';

i modifier: insensitive. Case insensitive match (ignores case of [a-zA-Z])

edited Sep 24, 2017 at 0:41

answered Sep 24, 2017 at 0:37

Duc Filan

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chris85 · Accepted Answer · 2017-09-24 00:49:00Z

2

A better approach to this would be using a parser and then use a regex on just the attributes value.

$html = '<meta name="generator" content="WordPress 4.8.2">';
$dom = new DOMDocument;
$dom->loadHTML($html);
$heads = $dom->getElementsByTagName('meta');
foreach ($heads as $head) {
    if($head->getAttribute('name') == 'generator' && preg_match('/wordpress (?<version>(?:\d+\.?)+)/i', $head->getAttribute('content'), $version)) {
        die($version['version']);
    }
}

Demo: https://3v4l.org/YlsFP

answered Sep 24, 2017 at 0:49

chris85

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