1

Comparison between these two lists and eliminating from List1 if it matches. Is there any way to process the List1 too.

List1: ["'file',", "'ist',", "'customer',"]

List2: ['permission', 'ist', 'dr']
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4
  • What do you mean by process the list? Commented May 25, 2018 at 17:16
  • 1
    Can you post your expected output? Commented May 25, 2018 at 17:16
  • processing List means List1 to ['file', 'ist', 'customer'] to make processing easier. @S Commented May 25, 2018 at 17:27
  • expected output should eliminate 'ist' from list1 Commented May 25, 2018 at 17:28

2 Answers 2

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5

Seems like a simple list comprehension would do it.

filtered_list = [string for string in List1 if string not in List2]

Warning: your strings in List1 don't match the format of the strings in List2. Not sure if that was your intent. The string 'ist', won't match with the string ist.

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4 Comments

for what it's worth this isn't the most efficient as it's O(n^2) running time
actually i know to do comparison, the format of the list1 is creating problem. How to handle that.
The cleanest approach would probably be creating a new list with the strings cleaned up. str.strip might do it, depending on what other formatting errors are in those strings. cleaned_list_1 = [x.strip(['"', "'", ',']) for x in List1]
@Tnguyen True. It would run in O(n) if he used set(List2) and searched in the set instead of in List2 directly.
2

This will give you the required output.

for i in list(List1):
    if i.strip("',") in List2:
        List1.remove(i)
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1 Comment

You are just so awesome.. was stuck at it from morning.. brilliant!! thanks!!

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