Is it possible to overload the action methods based on number of parameters in request?
Eg:
1.
domain.com/List/Filter/ByName
invokes -> public ActionResult Filter(string criteria1)
2.
domain.com/List/Filter/ByName/ByRanking
invokes -> public ActionResult Filter(string criteria1, string criteria2)
I'm using asp.net mvc2.
Action methods cannot be overloaded based on parameters because there would be no reasonable way to disambiguate a URL into multiple overloaded methods.
What you can do, though is either this:
public ActionResult Filter(string criteria1, string criteria2)
and then check whether criteria2 is null to filter only by name.
Alternatively, you can use ActionNameAttribute to decorate your action methods
[ActionName("FilterByName")]
public ActionResult Filter(string criteria1)
[ActionName("FilterByNameAndRanking")]
public ActionResult Filter(string criteria1, string criteria2)
and then use that name in route registration. This approach, however, can lead to much confusion.
If I'm not mistaken the best way to do this would be to add two different controller methods and map them to two different Urls.
public ActionResult Filter1(string criteria1);
public ActionResult Filter2(string criteria1, criteria2);
Then you have two route definitions:
This will map this URL List/Filter/xxCriteria/ to the first controller
routes.MapRoute(
"Filter", // Route name
"{controller}/Filter/{criteria1}", // URL with parameters
new { controller = "List", action = "Filter1", criteria="" } // Parameter defaults
);
This will map this URL List/Filter/xxCriteriaName/xxxCriteriaRank to the second controller. Without this route you could still map a url to the second method, but it would look like : List/Filter/?criteria1=xx&criteria2=xx
routes.MapRoute(
"Filter2", // Route name
"{controller}/Filter/{criteria1}/{criteria2}", // URL with parameters
new { controller = "List", action = "Filter2", criteria1 = "", criteria2 = "" } // Parameter defaults
);
Hope it helped.
{criteria1} I forgot the 1 See my edit history. Changed it in the answer.