Searching and Modifying NSMutableArray object with updated values

Question

I have constructed my model object with following.

@property (strong, nonatomic) NSString *id;
@property (strong, nonatomic) NSString *somevalue;
@property (strong, nonatomic) NSString *another value;
@property (strong, nonatomic) NSString *xtz;
@property (strong, nonatomic) NSString *st;
@property (strong, nonatomic) NSMutableArray *sc;

Now my mutable array is filled with following sample objects,

{a = 1;b = 6;c = 0;},{a = 2;b = 7;c = 0;},{a = 2;b = 8;c = 0;},{a = 3;b=9;c = 0;}

There are roughly 200 of such objects in my array. Now I cannot figure out a decent way of looping through the array updating the value of for example 'c' to '1' where 'a' ==1.

I could use a for loop like that:

for(int i = 0 ; i <myobject.sc.count; i++) {
    NSLog(@"%@",[[myobject sc]objectAtIndex:i]);
}

It would allow me to iterate through the array. But still face the problem of looping through values contains within each object. Maybe a nested loop?

Possible duplicate of NSArray find object or objects - best practices — Willeke
– Willeke, Commented Sep 1, 2018 at 21:33
@Willeke this is not duplicate question. Please read carefully before jumping to conclusions — humble_pie
– humble_pie, Commented Sep 1, 2018 at 22:54

rmaddy · Accepted Answer · 2018-09-02 00:13:20Z

0

All you need is a simple loop:

for (WhateverDataType *data in myobject.sc) {
    if (data.a == 1) {
        data.c = 1
        // break // uncomment if you only want to update the first match
    }
}

This gives you a general idea for the solution. The specific syntax depends on what type of objects are actually in the mutable array.

answered Sep 2, 2018 at 0:13

rmaddy

319k44 gold badges548 silver badges591 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Searching and Modifying NSMutableArray object with updated values

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related