Extract part of string using REGEX

Question

I need to extract following from below string using REGEX, can anyone help

String = "[payment is made within [ 10  ] Business Days  of its due date.]"

Output:

[ 10  ] Business Days

You need to specify what exactly are you looking for. Is is a substring containing a number of "Business Days"? Is it the string containing 2 words after number 10 in square brackets? Spaces are important too. Will there always be a space between number and brackets? Add more details. — IcedLance
– IcedLance, Commented Sep 29, 2018 at 18:31
If you just want to find that substring with varying number of days, it would be ([ [0-9]+ ] Business Days). — IcedLance
– IcedLance, Commented Sep 29, 2018 at 18:42

nitzien · Accepted Answer · 2018-09-29 19:18:52Z

1

Please try this.

s/^\[payment is made within (\[ [0-9]* \]) Business Days.*$/\1 Business Days/

answered Sep 29, 2018 at 18:30

nitzien

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10 Comments

can you try here - regexr.com... im trying above regex and it doesn't work

Maybe [0-9]+? Also I don't use regexp much, but is s/*/*/ a standard syntax or is it specific to sed?

It is working. I am using PCRE engine. Which one are you using?

Use this link regexr.com/40cfn. And then under tool, add following text- "\1 Business Days" without quotes. And use replace option.

@IcedLance It is specific to SED. But I feel it as good shorthand to write whenever somebody asks for regex.

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