I would like to display the attributes of a give object and was wondering if there was a python function for it. For example if I had an object from the following class:
class Antibody():
def __init__(self,toSend):
self.raw = toSend
self.pdbcode = ''
self.year = ''
Could I get an output that looks something like this or something similar:
['self.raw','self.pdbcode','self.year']
thanks
Try dir(self). It will include all attributes, not only "data".
The following method prints ['self.pdbcode', 'self.raw', 'self.year'] for an instance of your class:
class Antibody():
...
def get_fields(self):
ret = []
for nm in dir(self):
if not nm.startswith('__') and not callable(getattr(self, nm)):
ret.append('self.' + nm)
return ret
a = Antibody(0)
print a.get_fields()
Like this
class Antibody:
def __init__(self,toSend):
self.raw = toSend
self.pdbcode = ''
self.year = ''
def attributes( self ):
return [ 'self.'+name for name in self.__dict__ ]
a = Antibody(0)
map(lambda attr: 'self.%s'%(attr), filter(lambda attr: not callable(getattr(a, attr)), a.__dict__))
