I have a [[String]] like
myArr = [["1_2","1_3","1_4"], ["2_1","2_2","2_3"], ["3_1","3_2","3_3"]] then
I Want to remove element like this
bypassArr = ["1_2","2_3","3_2"]
how to remove bypassArr from myArr using element. or how can i get this type of result.
result = [["1_3","1_4"], ["2_1","2_2"], ["3_1","3_3"]]
If the intention is to remove all elements from bypassArr in the “inner” arrays from myArr then a combination of map() and filter() does the trick:
let myArr = [["1_2","1_3","1_4"], ["2_1","2_2","2_3"], ["3_1","3_2","3_3"]]
let bypassArr = ["1_2","2_3","3_2"]
let result = myArr.map { innerArray in
innerArray.filter { elem in
!bypassArr.contains(elem)
}
}
print(result)
// [["1_3", "1_4"], ["2_1", "2_2"], ["3_1", "3_3"]]
The inner arrays are filtered to remove the given elements, and the outer array is mapped to the filtered results.
Or with short-hand parameter notation:
let result = myArr.map { $0.filter { !bypassArr.contains($0) }}
var myArr = [["1_2","1_3","1_4"], ["2_1","2_2","2_3"], ["3_1","3_2","3_3"]]
let bypassArr = ["1_2","2_3","3_2"]
if myArr.count == bypassArr.count {
myArr = bypassArr.enumerated().map({ (index, str) -> [String] in
if let strPos = myArr[index].firstIndex(of: str) {
myArr[index].remove(at: strPos)
}
return myArr[index]
})
}
print(myArr)
