Using default constructor in non-default constructor

Question

When overloading constructors, is it possible to have a non-default constructor call the default constructor, so that I am not copy-pasting the code from the default constructor into any later non-default constructors? OR what is the reason for not allowing this functionality?

Here's my code:

class Test{
    private:
        int age;
        int createdAt;
    public:
        //Here is the defualt constructor.
        Test(){
            this->createdAt = 0;
        };
        //Non-default constructor calling default constructor.
        Test(int age){
            this->Test(); //Here, call default constructor.
            this->age = age;
        };
};

Do note that this code throws the compiler error "Invalid use of Test::Test", so I'm obviously doing something incorrect.

Thanks for your time!

C++11 - Delegating Constructors.. those are the keywords you can search for.. stackoverflow.com/q/13961037/1462718 — Brandon
– Brandon, Commented Apr 9, 2019 at 3:26
BTW there's no need for this-> in this->createdAt. createdAt= 0; works just fine. On most modern compilers you can put int createdAt= 0; so there's no need for that either. — Mirko
– Mirko, Commented Apr 9, 2019 at 3:27
Note also you're not initializing age on the default constructor; that goes away if you put int age= 0; — Mirko
– Mirko, Commented Apr 9, 2019 at 3:28

Remy Lebeau · Accepted Answer · 2019-04-09 04:44:44Z

3

Yes it is possible with the help of delegating constructor. This feature, called Constructor Delegation, was introduced in C++ 11. Take a look at this,

#include<iostream>  
using namespace std;
class Test{
    private:
        int age;
        int createdAt;
    public:
        //Here is the defualt constructor.
        Test(){            
            createdAt = 0;
        };

        //Non-default constructor calling default constructor.
        Test(int age): Test(){ // delegating constructor
            this->age = age;
        };

        int getAge(){
            return age;
        }

        int getCreatedAt(){
            return createdAt;
        }
};

int main(int argc, char *argv[]) {
    Test t(28);
    cout << t.getCreatedAt() << "\n";
    cout << t.getAge() << "\n";
    return 0;
}

edited Apr 9, 2019 at 4:44

Remy Lebeau

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answered Apr 9, 2019 at 4:17

user10704605

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