Javascript check all values of object and it's nested object

Question

Hi i'm currently stuck with this problem of checking an object that has another nested object if all value in it is null or 0

My object is as follow:

{
   "city":0,
   "road":{
      "max":null,
      "min":null
   },
   "size":{
      "max":null,
      "min":null
   },
   "type":null,
   "ward":0,
   "floor":null,
   "price":{
      "max":null,
      "min":null
   },
   "street":0,
   "toilet":null,
   "balcony":null,
   "bedroom":null,
   "district":0,
   "frontend":{
      "max":null,
      "min":null
   },
   "direction":null,
   "living_room":null
}

i need to check every single values in it is 0 or null , return true if all values is either 0 or null, false if any of the values different than null or 0

i can't use :

Object.values(object).every(i => (i === null || i === ''))

It return False since the nested object still consider as a different value than 0 and null

I don't want to write super long if condition check every single value of it at a time

Is there anyway to iterate over the object and it's nested object to check ?

Nina Scholz · Accepted Answer · 2019-10-25 07:49:42Z

3

You could take an iterative and recursive approach.

function check(object) {
    return Object.values(object).every(v => v && typeof v === 'object'
        ? check(v)
        : v === 0 || v === null
    );
}

var data0 = { city: 0, road: { max: null, min: null }, size: { max: null, min: null }, type: "sell", ward: 0, floor: null, price: { max: null, min: null }, street: 0, toilet: null, balcony: null, bedroom: null, district: 0, frontend: { max: null, min: null }, direction: null, living_room: null },
    data1 = { city: 0, road: { max: null, min: null }, size: { max: null, min: null }, type: null, ward: 0, floor: null, price: { max: null, min: null }, street: 0, toilet: null, balcony: null, bedroom: null, district: 0, frontend: { max: null, min: null }, direction: null, living_room: null };

console.log(check(data0)); // false because of type: "sell"
console.log(check(data1)); // true

edited Oct 25, 2019 at 7:49

answered Oct 25, 2019 at 7:37

Nina Scholz

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3 Comments

Linh Nguyen Over a year ago

shouldn't it return true if every v equal null or 0 ? or am i mistaken ?

Nina Scholz Over a year ago

right, it does. but you have type: "sell", which is not null or zero.

Linh Nguyen Over a year ago

oh yeah my bad forgot to edit that, type supposed to be null

CertainPerformance · Accepted Answer · 2019-10-25 07:34:42Z

2

One (inelegant) option is to use JSON.stringify with a callback, and whenever a value other than 0 or null is found, set a flag:

const obj = {
   "city":0,
   "road":{
      "max":null,
      "min":null
   },
   "size":{
      "max":null,
      "min":null
   },
   "type":"sell",
   "ward":0,
   "floor":null,
   "price":{
      "max":null,
      "min":null
   },
   "street":0,
   "toilet":null,
   "balcony":null,
   "bedroom":null,
   "district":0,
   "frontend":{
      "max":null,
      "min":null
   },
   "direction":null,
   "living_room":null
};

let allZeroNull = true;
JSON.stringify(obj, (key, val) => {
  if (typeof val !== 'object' && val !== 0) {
    allZeroNull = false;
  }
  return val;
});
console.log(allZeroNull);

Or, to do it more manually, with short-circuiting:

const obj = {
   "city":0,
   "road":{
      "max":null,
      "min":null
   },
   "size":{
      "max":null,
      "min":null
   },
   "type":"sell",
   "ward":0,
   "floor":null,
   "price":{
      "max":null,
      "min":null
   },
   "street":0,
   "toilet":null,
   "balcony":null,
   "bedroom":null,
   "district":0,
   "frontend":{
      "max":null,
      "min":null
   },
   "direction":null,
   "living_room":null
};

const isAllZeroNull = (item) => {
  if (typeof item === 'object' && item !== null) {
    for (const val of Object.values(item)) {
      if (!isAllZeroNull(val)) {
        return false;
      }
    }
  } else if (item !== 0 && item !== null) {
    return false;
  }
  return true;
};
console.log(isAllZeroNull(obj));

answered Oct 25, 2019 at 7:34

CertainPerformance

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2 Comments

Jasmonate Over a year ago

That... is silly but impressive and deserves an upvote.

Shawn Mclean Over a year ago

LMAO! I'm here just trying to really search if a property with a specific name or value exists and never thought to just dump it to a JSON string and search that.

Ori Drori · Accepted Answer · 2019-10-25 07:37:58Z

1

You can can create a function (fn) that uses Object.values() to get an array of values, iterate with Array.every() and if the value is an object use fn on it:

const fn = data =>
  Object.values(data)
  .every(v => {
    if(v === null || v === 0) return true;
    
    return typeof v === 'object' ? fn(v) : false;
  })

const data = {"city":0,"road":{"max":null,"min":null},"size":{"max":null,"min":null},"type":"sell","ward":0,"floor":null,"price":{"max":null,"min":null},"street":0,"toilet":null,"balcony":null,"bedroom":null,"district":0,"frontend":{"max":null,"min":null},"direction":null,"living_room":null}

const result = fn(data)

console.log(result)

answered Oct 25, 2019 at 7:37

Ori Drori

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