Newbie python - replace in an array

Question

In a file, I have the following lines

NetConn_msa[0].time=0.0

NetConn_msa[1].time=0.0 etc for 60 elements.

I need to write a script to change the time from 0.0 to 0.5.

I started with st.replace("delay=0.0","delay=0.05") and then tried to find the string to replace

sub=re.compile("\[\d+\]\.\w+=[0]\.[0]")
result=sub.search(st)

Can someone please help me since I am very new to programming. Thanks!

You have not really asked a question.

Achim
– Achim

2011-05-02 20:51:08 +00:00
Commented May 2, 2011 at 20:51 — Achim
– Achim, Commented May 2, 2011 at 20:51
What are you trying to achieve, in the first place?

Santa
– Santa

2011-05-02 21:13:08 +00:00
Commented May 2, 2011 at 21:13 — Santa
– Santa, Commented May 2, 2011 at 21:13

John Machin · Accepted Answer · 2011-05-02 22:27:45Z

2

Why not do this the really easy way: manually edit the file so that the offending 60 lines are replaced by:

for x in range(60):
    NetConn_msa[x].time = 0.5

answered May 2, 2011 at 22:27

John Machin

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John Machin · Accepted Answer · 2011-05-02 21:58:57Z

1

Script:

import re

x = """NetConn_msa[0].time=0.0
NetConn_msa[59].time=0.0
NetConn_msa[0].time=9.9
NetConn_msa[60].time=0.0
NetConn_msa[61].time=0.0
NetConn_msa[99].time=0.0
NetConn_msa[100].time=0.0
NetConn_msa[0].other=0.0
NetConn_msa[0].time=0.01
PseudoNetConn_msa[59].time=0.0
Foo[0].bar=0.0"""

print "=== not strict enough ==="
print re.sub("(\]\.\w+)=0.0","\\1=0.5",x)

print "=== stricter ==="
print re.sub(r"(NetConn_msa\[[1-5]?\d\]\.time)=0.0\b", r"\1=0.5", x)

Output:

=== not strict enough ===
NetConn_msa[0].time=0.5
NetConn_msa[59].time=0.5
NetConn_msa[0].time=9.9
NetConn_msa[60].time=0.5
NetConn_msa[61].time=0.5
NetConn_msa[99].time=0.5
NetConn_msa[100].time=0.5
NetConn_msa[0].other=0.5
NetConn_msa[0].time=0.51
PseudoNetConn_msa[59].time=0.5
Foo[0].bar=0.5
=== stricter ===
NetConn_msa[0].time=0.5
NetConn_msa[59].time=0.5
NetConn_msa[0].time=9.9
NetConn_msa[60].time=0.0
NetConn_msa[61].time=0.0
NetConn_msa[99].time=0.0
NetConn_msa[100].time=0.0
NetConn_msa[0].other=0.0
NetConn_msa[0].time=0.01
PseudoNetConn_msa[59].time=0.0
Foo[0].bar=0.0

edited May 2, 2011 at 21:58

answered May 2, 2011 at 21:38

John Machin

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5 Comments

Aif Over a year ago

I think your "stricter" entry is the same as "no strict enough"

John Machin Over a year ago

@Aif: If you mean that my longer version is still not strict enough, please give an example; otherwise, please explain what you mean.

Aif Over a year ago

Sorry it was unclear: look the output. Stricter also matched Foo[O].bar=0.0.

John Machin Over a year ago

@Aif: You are mistaken. Look at the output. "Stricter" did NOT change the 0.0 to 0.5.

Aif Over a year ago

Sorry, I didn't figure out the "sub" stuff. (was late.. :p)

YOU · Accepted Answer · 2011-05-02 20:55:36Z

0

x = """NetConn_msa[0].time=0.0

NetConn_msa[1].time=0.0 etc for 60 elements. """

print re.sub("(\]\.\w+)=0.0","\\1=0.5",x)

#NetConn_msa[0].time=0.5

#NetConn_msa[1].time=0.5 etc for 60 elements.

answered May 2, 2011 at 20:55

YOU

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Comments

Tyler Eaves · Accepted Answer · 2011-05-02 22:01:41Z

0

Why not do this the easy way?

st.replace('.time=0.0\n','.time=0.5\n')

answered May 2, 2011 at 22:01

Tyler Eaves

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1 Comment

John Machin Over a year ago

Because you could change text that should not be changed, and not change text that should be changed. Examples of the latter: '.time=0.0 \n' and '.time=0.0 # comment\n'

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