ruby array with arrays how to get the array number when iterating over each of them and searching by number

Question

if I get from params something like a 165. and this is number contains in array number 3 of 9. how to get this number of the array?

range = 50..450
cutter = range.last/50
b = range.each_slice(range.last/cutter).to_a

b #=> [[50, 51,..., 99],..., [400, 401,..., 450]]

How to get it?

In your code, the variable a is undefined. Also, i don't understand what b is supposed to represent, since the expression [[50..99]..[400..450]] is not valid Ruby (the lower/upper bound of a range can't be an array). — user1934428
– user1934428, Commented Jan 23, 2020 at 10:22
@user1934428 sorry, i updated. b in my example return array of 9 arrays. each array have a 50 numbers, — user2369480
– user2369480, Commented Jan 23, 2020 at 10:25
Even after the update, the two problems I mentioned in my comment are still there ...... Did you ever actually execute the code you posted? Please write a complete example, which we can reproduce in irb, describe the output you receive, and the output you would like to see. — user1934428
– user1934428, Commented Jan 23, 2020 at 10:28
Your code produces the array b #=> [[50, 51,..., 99],..., [400, 401,..., 449], [450]]. — Cary Swoveland
– Cary Swoveland, Commented Jan 24, 2020 at 17:47

ReggieB · Accepted Answer · 2020-01-23 10:33:18Z

2

The array method you want is find_index. I think this will do what you want:

b.find_index {|a| a.include?(165)}

answered Jan 23, 2020 at 10:33

ReggieB

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ReggieB Over a year ago

@CarySwoveland I think you are wrong. I've just tried it and get NoMethodError (undefined method 'include?' for 50:Integer). find_index iterates over the outer arrays in the block, so a is always one of the inner arrays.

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