Django query params to array

Question

I am trying to get the results from an array as explained here: https://docs.djangoproject.com/en/dev/ref/models/querysets/#in

http://127.0.0.1:8000/blogs?years=['2018', '2019']
http://127.0.0.1:8000/blogs?years=[2018, 2019]

Turns out ['2018', '2019'] is not what i am getting as years , even though visually they look exactly the same.

I even tried using getlist as explained here how to get multiple results using same query params django this does produce the desired results

def get_queryset(self):
        years = self.request.query_params.get('years')
        return self.queryset.filter(year__in=years)

Any clue on what am i doing wrong here?

I tried all options it does not work, while i type in the below statement it works perfectly fine

def get_queryset(self):
        return self.queryset.filter(year__in=['2018', '2019'])

DevOps Craftsman · Accepted Answer · 2021-03-25 12:58:37Z

28

I don't believe this way will work. When you pass the value in querystring, I guess Django will recieve as a string.

- EDIT -

The above answer wont work is need to add more years, I got the solution 127.0.0.1:8000/blogs?years=2018&years=2019 and

years = self.request.query_params.getlist('years', '')

converts this to list.

– @indavinci

edited Mar 25, 2021 at 12:58

DevOps Craftsman

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answered Feb 1, 2020 at 1:45

Thiago Schettini

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2 Comments

indavinci Over a year ago

The above answer wont work is need to add more years, I got the solution 127.0.0.1:8000/blogs?years=2018&years=2019 and years = self.request.query_params.getlist('years', '') converts this to list.

Thiago Schettini Over a year ago

Perfect! Will add your solution to the answer ;)

uzt565lwz · Accepted Answer · 2021-08-05 01:42:18Z

7

If you have function based view this should work:

request.GET.getlist('years', '')

answered Aug 5, 2021 at 1:42

uzt565lwz

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1 Comment

Eddy Irwan Bin Mahamad Over a year ago

years = request.GET.getlist('years', [] )

Ishant Dahiya · Accepted Answer · 2021-08-22 22:36:25Z

6

I think a better a better and cleaner way to solve this problem is to just pass the string as comma-separated values in query params and split them up in your Django View.

URL:

http://127.0.0.1:8000/blogs?years=2018,2019

Your View:

def get_queryset(self):
    years = self.request.query_params.get('years').split(',')
    return self.queryset.filter(year__in=years)

answered Aug 22, 2021 at 22:36

Ishant Dahiya

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1 Comment

Original BBQ Sauce Over a year ago

this is the way

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