How to avoid "if" nesting when need Multiple return values in python

Question

Like this,assume I need use some library function(I can not change them),it return a value or None, I want use the returned value and pass it to another function. How to avoid use many if statements at the same time?

Here is an example of my code:

import random
def somefunction1(n):
    m=random.randint(0,n)
    if m>5:
        return None
    else:
        return m

def somefunction2(n):
    # like somefunction1

# ------way one
r1=somefunction1(10)
r2=somefunction2(someParameter)
if r1:
    print(r1)
elif r2:
    print(r2)

# --------way two
r1=somefunction1(10)
if r1:
    print(r1)
else:
    r2=somefunction2(someparameter)
    if r2:
        print(r2)

Your question is not clear. What exactly is your question? Please check how to ask to learn how to write a good question. — dspencer
– dspencer, Commented Mar 15, 2020 at 12:18
I am not good at english,the description may be a bit vague.The code is pseudo-code. I search,find link this,but it can not use parameter. — gaofei
– gaofei, Commented Mar 15, 2020 at 12:34

Kelly Bundy · Accepted Answer · 2020-03-15 12:52:36Z

1

if r := somefunction1(10) or somefunction2(someParameter):
    print(r)

answered Mar 15, 2020 at 12:52

Kelly Bundy

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2 Comments

Kelly Bundy Over a year ago

@krishna Woah, Python 8... welcome to the 21st, traveler :-)

krishna Over a year ago

Sorry, Python3.8 I mean to say.

Harshit Jindal · Accepted Answer · 2020-03-15 12:40:22Z

0

Try this:

def a_function(parameters):
    default_value = None

    apply_some_operation_on(parameters):
        if YouWantToReturnSomething:
            default_value = whatever_you_want_to_return

    return return_val

answered Mar 15, 2020 at 12:40

Harshit Jindal

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Comments

krishna · Accepted Answer · 2020-03-15 12:51:21Z

0

Please check this, If you are not using out_put1 as input for another function then you can use like this.
If function1() return some value then out_put value will be that value.
else if function2() returns some value that then out_put will be value of function2() else it will be None

out_put =  function1() or function2()
if out_put:
    print(out_put)

edited Mar 15, 2020 at 12:51

answered Mar 15, 2020 at 12:34

krishna

1,0297 silver badges12 bronze badges

1 Comment

gaofei Over a year ago

Thank you, both this and this are good.

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