How do I add a custom struct to an array in C?

Question

I have a custom structure called pair, which has two arguments: int winner, and int loser

typedef struct
{
    int winner;
    int loser;
}
pair;

I also have an array of pairs called pairs, but when I attempt to add a pair to the array, it says,

tideman.c:157:37: error: expected expression
                pairs[pair_count] = {i, j};

Is there a problem with using curly bracket notation for adding structures to arrays in C? If I make a variable for adding pairs, will it change all the pairs in the array every time I add a new pair (due to mutability problems)?

    for (int i = 0; i < candidate_count; i++)
    {
        for (int j = 0; j < candidate_count; i++)
        {
            if (preferences[i][j] > preferences[j][i])
            {
                pairs[pair_count] = {i, j};
            }
        }
    }

Petr Skocik · Accepted Answer · 2020-07-04 19:33:47Z

3

{i, j} would only work in an initialization (pair x = {i, j};). pairs[pair_count] = {i, j}; would be an assignment, and there you need a variable of type pair as the right-hand side. The most straightforward way to obtain one would be to use a compound literal pairs[pair_count] = (pair){i, j};. Alternatively, you can assign to each member separately (pairs[pair_count].winner=i; pair[pair_count].loser=j;).

answered Jul 4, 2020 at 19:33

Petr Skocik

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