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So, I was doing some automation for Google Play Store(website from computer).

This is the element I am looking to click.

This is the menu which opens when we click the 3 dots on side of review. I have to click one of these 3 menu options then. I am not able to use .click() function on any of these 3 items. All of these 3 span elements of menu are contained in a single div parent.

When I use

element = driver.find_element_by_xpath('/html/body/div[1]/div[4]/c-wiz/div/div[2]/div/div/main/div/div[1]/div[3]/div/div[2]/div[1]/div[2]/div/div[2]/div[2]/div/div/div/span[2]/div[2]')
element.click()

It gives:

ElementNotInteractableException: Message: Element <div class="uyYuVb oJeWuf"> could not be scrolled into view

I tried to click the span, and also its child elements like div which has display:flex also the last div child. But all of them gave the same exception. I know Play Store is mainly for mobile and therefore it is showing the properties of a mobile element. What is the appropriate way to click any of these 3 options then?

here is the link:

1 Answer 1

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I don't think it is possible to click on a span like this one using selenium. However I think you should try getting the position of this span on the screen so you can click on it using a module like pyautogui :

import pyautogui
pyautogui.click(x=positionx, y=positiony)

This is the only solution I found and I hope you will not have to do it a lot of time in your program since it's repetitive and annoying (to find the x and y positions)

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2 Comments

the position of this span might change with Window size and even by a slightest change might break the code this way, U mean we would have to hardcode the values of positions right? isn't there any other way to simulate the behaviour of clicking that menu items?
If the position of the span changes with the window size you should try maximizing the size of the window (fullscreen) so it's always at the same point. stackoverflow.com/questions/12211781/…

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