Get unique list of strings by string substring

Question

I made this working code but maybe it's possible to make it shorter?

sents_str = 'dimplegalla:28082000 dimplegalla:28082000'

sents = sents_str.split(' ')
uniqueList = []
uniqueRes = []

for letter in sents:
    if letter.split(':')[1] not in uniqueList:
        uniqueList.append(letter.split(':')[1])
        uniqueRes.append(letter)
print(uniqueRes)

note: you disregard any differences in the first part of the .split(':') (which happens to always be 'dimplegalla' in your example). Is that intentional? — Pierre D
– Pierre D, Commented Dec 29, 2020 at 20:20
Given just the code you have posted, then: print([sents_str.split()[0]]). But I'm not sure this is what you want. — quamrana
– quamrana, Commented Dec 29, 2020 at 20:29
what is the expected output if sents_str = 'dimplegalla0:28082000 dimplegalla1:28082000'? And what about 'a:0:0 b:0:1'? — Pierre D
– Pierre D, Commented Dec 29, 2020 at 20:36

Czaporka · Accepted Answer · 2020-12-29 20:31:39Z

1

How about this:

In [1]: sents_str = 'dimplegalla:28082000 dimplegalla:28082000'

In [2]: list(set(sents_str.split()))
Out[2]: ['dimplegalla:28082000']

answered Dec 29, 2020 at 20:31

Czaporka

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Pierre D · Accepted Answer · 2020-12-29 20:17:54Z

0

Yes:

list({sub for sub in sents_str.split()})

answered Dec 29, 2020 at 20:17

Pierre D

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Comments

mrkasri · Accepted Answer · 2020-12-29 20:56:19Z

0

try this:

sents_str = 'dimplegalla:28082000 dimplegalla:28082000'
uniqueList= [l.split(':')[1] for l in list(set(sents_str.split(' ')))]
uniqueRes = list(set(sents_str.split(' ')))
print(uniqueList)
print(uniqueRes)

answered Dec 29, 2020 at 20:56

mrkasri

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