How to hit the Next button from Python using Selenium?

Question

I am trying to work with the following site using Python. Please advise how can I hit the Next button:

I have tried the following:

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC 
from selenium.webdriver.common.action_chains import ActionChains
import time

driver = webdriver.Chrome(executable_path = r'C:/chromedriver.exe')
driver.maximize_window()

wait = WebDriverWait(driver,40)

driver.get('https://www.okcupid.com/login')

driver.execute_script('arguments[0].click();',wait.until(EC.element_to_be_clickable((By.ID, 'username'))))
wait.until(EC.element_to_be_clickable((By.ID, 'username'))).send_keys("abc")

driver.execute_script('arguments[0].click();',wait.until(EC.element_to_be_clickable((By.ID, 'username'))))
wait.until(EC.element_to_be_clickable((By.ID, 'password'))).send_keys("123")

# Find login button
login_button = driver.find_element_by_name('Next')
# Click login
login_button.click()

But got an error:

NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":"[name="Next"]"}

DMart · Accepted Answer · 2021-01-14 21:41:33Z

1

Name is a an attribute on a webelement. The next button has no Name attribute.

You can try this xpath:

//input[@value='Next']

login_button = driver.find_element_by_xpath('//input[@value="Next"]')

answered Jan 14, 2021 at 21:41

DMart

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