In PHP, is it possible to declare a method in a class only if a statement is true :
class MyClass {
//...
if (mode === 'production'):
public function myMethod() {
// My cool stuffs here
}
endif;
}
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2No it isn't ...AbraCadaver– AbraCadaver2021-10-09 05:09:00 +00:00Commented Oct 9, 2021 at 5:09
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1No, but you can certainly solve whatever problem you are trying to solve some other way. For example you could use inheritance, or a factory pattern, or perhaps pass an object into the class that either does or does not have the method defined.gview– gview2021-10-09 05:34:28 +00:00Commented Oct 9, 2021 at 5:34
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2 Answers
No you can't, but there are certainly some alternative solutions like using inheritance.
Comments
You can limit your function work by creating
objectand calling themethodof yourclassthrough your condition. For example,
class MyClass {
public function myMethod() {
// My cool stuffs here
return 'Hello there';
}
}
$myObj = new MyClass();
$mode = 'production';
if ($mode === 'production'):
echo $myObj->myMethod();
endif;
Even you can use the constructor method and pass the
$modevalue and then return value only condition is true.
class MyClass {
private $mode;
function __construct($mode) {
$this->mode = $mode;
}
public function myMethod() {
// My cool stuffs here
if($this->mode == 'production'){
return 'Hello there';
}
return '';
}
}
$myObj = new MyClass('production');
echo $myObj->myMethod();
