logically this makes sense but does not work.
dice = 0
while True:
dice = int(input("enter dice: "))
if (dice != 4 or dice != 6 or dice != 8 or dice != 10 or dice != 12 or dice != 20):
print("invalid")
elif (dice == 4 or dice == 6 or dice == 8 or dice == 10 or dice == 12 or dice == 20):
print("valid")
break
print("Accepted dice")
I keep getting the invalid print statement. Want to have it as a loop until one of the correct die is selected.
use a flag, as mentioned in the comment your original first if is flawed ... if you just want to fix it then you can change your or's to and's
dice_is_valid = dice in {4,6,8,10,20}
if dice_is_valid:
...
else:
print("invalid")
The problem is with using an or statement here. Take for example an input of 4. 4 != 4 if obviously false, but then it evaluates 4 != 6 which is true. No matter what you input that first condition will always be true because of this. Instead just use an else statement like so
dice = 0
while True:
dice = int(input("enter dice: "))
print("invalid")
if (dice == 4 or dice == 6 or dice == 8 or dice == 10 or dice == 12 or dice == 20):
print("valid")
break
else:
print("invalid")
print("Accepted dice")
dice_var = 0
a = [4,6,8,10,12,20]
while True:
dice_var = int(input("Enter the dice value ;"))
if dice_var in a:
print("Valid Value !!!!")
break
else:
print("Invalid Value !!!!")
print("Accepted Dice")
ifis flawed, it will always evaluate as true. Takedice != 4 or dice != 6, it can never be false, the first part will only be false ifdice == 4but that makes the second part true