Function Value hints python

Question

I have couple of functions on a python code and I want to use value hints. This function does not give me any errors:

def function1(self, a: int, b: int = 0):

But when I want to add another parameter to the function it gives me an error:

def function1(self, a: int, b: int = 0, c: int):

SyntaxError: non-default argument follows default argument

Do you know if there is any way to solve this, so that I can have a non-default argument following a default argument?

How do you expect to call that, provide a value for c but let b take the default? If you want c to be keyword-only see e.g. stackoverflow.com/a/37829651/3001761, but this isn't related to the type hints - you'd have the same problem without them. — jonrsharpe
– jonrsharpe, Commented Oct 4, 2022 at 8:37
What do you think is a „Value hint“? In Python, default values and type homes are mechanisms. — MisterMiyagi
– MisterMiyagi, Commented Oct 5, 2022 at 5:16

Eddoasso · Accepted Answer · 2022-10-04 08:34:39Z

0

In python, arguments with default values must follow arguments with required values.

Try rewriting as def function1(self, a: int, c: int, b: int = 0,):

You can still call it by doing function1(self, a=a_val, b=b_val, c=c_val)

answered Oct 4, 2022 at 8:34

Eddoasso

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Ismaili Mohamedi · Accepted Answer · 2022-10-06 06:44:54Z

0

The error says: you can not make argument with no default value in parameter. that is a syntax rule from python. to make it works just add default values like this:

def function1(self, a: int, b: int = 0, c: int = 0):

edited Oct 6, 2022 at 6:44

Ismaili Mohamedi

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answered Oct 4, 2022 at 8:34

Henro Sutrisno Tanjung

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