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Python split string on regex
How do I split some text using Python's re module into two parts: the text before a special word cut and the rest of the text following it.
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4Welcome to SO! Please improve the quality of your question.user195488– user1954882011-09-21 12:49:03 +00:00Commented Sep 21, 2011 at 12:49
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A great way to improve the quality of your question is to search for all the questions which are exactly like this one. Here's a list: stackoverflow.com/search?q=python+re+split.S.Lott– S.Lott2011-09-21 13:45:27 +00:00Commented Sep 21, 2011 at 13:45
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2 Answers
You can do it with re:
>>> import re
>>> re.split('cut', s, 1) # Split only once.
But in this case you can just use str.split:
>>> s.split('cut', 1) # Split only once.
Comments
Check this, might help you
>>> re.compile('[0-9]+').split("hel2l3o")
['hel', 'l', 'o']
>>>
>>> re.compile('cut').split("hellocutworldcutpython")
['hello', 'world', 'python']
split about first cut
>>> l=re.compile('cut').split("hellocutworldcutpython")
>>> print l[0], string.join([l[i] for i in range(1, len(l))], "")
hello worldpython
4 Comments
Smirnov
need **TWO part ['hello', 'worldcutpython']
Aman Agarwal
can you please explain it clearly
Smirnov
Need text only before txt and after.
Aman Agarwal
>>> l=re.compile('cut').split("hellocutworldcutpython") >>> print l[0], string.join([l[i] for i in range(1, len(l))], "") hello worldpython