I need to declare an array that consists of different variable types, mainly:
char *A; uint32_t B; int C;
As I understood in the tutorials, in the array you declare the type and the number of element. So to say something like:
int a[3];
where in this case, the type of the three elements are all integers. So how do I want to declare an array that consists of the three different types mentioned above?
The definition of an array in C is a collection of elements of the SAME type. What you are looking for is probably a struct.
struct s
{
char* A;
uint32_t B;
int C;
};
int main(void)
{
struct s test;
test.A = "Hello";
test.B = 12345;
test.C = -2;
// Do stuff with 'test'
return 0;
}
Or, as mentioned in a comment below, you could use a union instead. But then you can't use A, B, and C at the same time like I have in the example above - only one of them will be stored - in my example it would be C.
You can make an array of structures if you need to.
struct s test[5]; // Array of structures
structs, ie in struct whatever array[100], the array has 100 elements, all of type struct whatever.You need to use union
i.e.
typedef struct {
int type;
union {
char *A;
uint32_t B;
int C;
}} item;
