Finding partial text match using any in Python [duplicate]

Question

I have a list of string that contains values like this:

I wish to find partial text match in my list using the any keyword:

result = any('abc' in w for w in list)

How can I find all the matching while ignoring upper case of lower case and yet find partial text match?

If that's what you want, then I would just add a lower() call so that the case is forced to lower: result = any("abc" in w.lower() for w in list1) — root
– root, Commented Oct 2, 2023 at 8:56

Jule · Accepted Answer · 2023-10-02 09:04:06Z

1

r = [w for w in list if 'abc' in w.lower()]

if you want to return the list of matched string

r = [if 'abc' in w.lower() for w in list ]

or a list of booleans.

Regular expression (see package re from the standard) or unix pattern matching (see package fnmatch) might be required for more sophisticated cases

answered Oct 2, 2023 at 9:04

Jule

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