Python exceptions: call same function for any Exception

Question

Notice in the code below that foobar() is called if any Exception is thrown. Is there a way to do this without using the same line in every Exception?

try:
  foo()
except(ErrorTypeA):
  bar()
  foobar()
except(ErrorTypeB):
  baz()
  foobar()
except(SwineFlu):
  print 'You have caught Swine Flu!'
  foobar()
except:
  foobar()

Finally will be executed if an no exceptions are thrown.

Jason Coon
– Jason Coon

2009-04-28 18:52:35 +00:00
Commented Apr 28, 2009 at 18:52 — Jason Coon
– Jason Coon, Commented Apr 28, 2009 at 18:52

FogleBird · Accepted Answer · 2009-04-28 18:42:01Z

18

success = False
try:
    foo()
    success = True
except(A):
    bar()
except(B):
    baz()
except(C):
    bay()
finally:
    if not success:
        foobar()

answered Apr 28, 2009 at 18:42

FogleBird

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Comments

Jochen Ritzel · Accepted Answer · 2009-10-13 21:11:43Z

12

You can use a dictionary to map exceptions against functions to call:

exception_map = { ErrorTypeA : bar, ErrorTypeB : baz }
try:
    try:
        somthing()
    except tuple(exception_map), e: # this catches only the exceptions in the map
        exception_map[type(e)]() # calls the related function
        raise # raise the Excetion again and the next line catches it
except Exception, e: # every Exception ends here
    foobar()

edited Oct 13, 2009 at 21:11

answered Apr 28, 2009 at 18:43

Jochen Ritzel

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1 Comment

Nathan Fellman Over a year ago

+1 didn't know that raise with no exceptions re-raises the exception

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