how vc++ debugger show pointer like array?

Question

when i have a var like char my_array[23] I can see it all the array value by click on name and expanding the array.

but I can do it when var is like char *my_data I see only first data.

how debugger in vc++ can have same behavior for this two case?

You don't know how many elements the pointer points to. The debugger doesn't know either. The only safe answer is "one". — Hans Passant
– Hans Passant, Commented Jan 26, 2012 at 10:31

Andriy Tylychko · Accepted Answer · 2012-01-25 16:33:18Z

1

Because they are different types, in the first case (char[23]) debugger knows how many elements are in array, the second case (char*) is just a pointer to char and debugger shows only the first element of the array

answered Jan 25, 2012 at 16:33

Andriy Tylychko

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herzl shemuelian · Accepted Answer · 2012-01-26 08:46:17Z

1

you must write in watch window

my_data,23

and can expand it like a array.

answered Jan 26, 2012 at 8:46

herzl shemuelian

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