Regular Expression String followed by digits in Javascript

Question

I am getting myArray as null. Can anyone help me?

myRe = new RegExp ("[A-Z]+(\\d+)");
myArray = myRe.exec("book1");
alert(myArray.length);

RichieHindle · Accepted Answer · 2009-05-29 11:31:22Z

7

Your regular expression is case sensitive; try:

myRe = new RegExp ("[A-Za-z]+(\\d+)");

or:

myRe = new RegExp ("[A-Z]+(\\d+)", "i");

answered May 29, 2009 at 11:31

RichieHindle

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2 Comments

Or add an i parameter: new RegExp('foo', 'i');

My fault I was using RegexBuddy with Case Insensitive mode turned on. Thank you for the quick answer.

Boris Guéry · Accepted Answer · 2009-05-29 11:36:57Z

2

It's because you use [A-Z] which is for uppercase.

Use this instead:

pattern = /[a-z](\d+)/i;
myArray = pattern.exec("BOOK1");
alert(myArray.length);

answered May 29, 2009 at 11:36

Boris Guéry

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